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From network 192.168.10.0/26, which two valid IP address can be assigned to hosts within the same subnet? (Choose two answers)
192.168.10.112
192.168.10.127
192.168.10.12
192.168.10.128
192.168.10.63
192.168.10.70
Network 192.168.10.0 255.255.255.192 (/26) has a block size of 64 (256-192), therefore if we start counting from 0 in multiples of 64, that is (0, 64, 128, 192) 4 subnets, or two bits on 11000000 (22 = 4). First subnet 192.168.10.0, the valid hosts are from 192.168.10.1 to 192.168.10.62, which there are no answers that fall into the same subnet. The second subnet 192.168.10.64, the valid hosts are from 192.168.10.65 to 192.168.10.127, which indeed there are two answers that fall into the same range.
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