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If the Redundancy of Parity is a concern, one should implement RAID 5 over RAID 3. True or False?
True
False
RAID 3, which is rarely used in practice, consists of byte-level striping with a dedicated parity disk. One of the characteristics of RAID 3 is that it generally cannot service multiple requests simultaneously, which happens because any single block of data will, by definition, be spread across all members of the set and will reside in the same location. Therefore, any I/O operation requires activity on every disk and usually requires synchronized spindles
RAID 5 consists of block-level striping with distributed parity. Parity information is distributed among the drives. It requires that all drives but one be present to operate. Upon failure of a single drive, subsequent reads can be calculated from the distributed parity such that no data is lost. RAID 5 requires at least three disks
[EDIT]What has this question got to do with DOS?
EDIT: This question is wrong. RAID 3 or 5 doesn't provide redundancy of parity. In each case there only 1 byte/block of parity for each byte/block of data you can only tolerate 1 failure. For example : RAID 6 could be used to increase parity redundancy (configured with 2 parity disk). Please correct this question.
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