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Using a class C address with subnet mask 255.255.255.240 (/28), what is the last valid host IP Address?
192.168.20.79
192.168.20.93
192.168.20.95
192.168.20.94
192.168.20.96
A class C address with a subnet mask 255.255.255.240 has a block size of 16 (256-240). Therefore if we start counting in blocks of 16 from 0 until we reach 80, which in the case of the question is the subnet address (192.168.20.80). If we add up another 16, the result is the next subnet address 192.168.20.96. Now if we focus on our subnet 192.168.20.80, we can get our broadcast address which is 192.168.20.95. And our first valid host is 192.168.20.81 and our last is 192.168.20.94 (which is always one before the broadcast address).
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